The approach uses a greedy algorithm with Roman numeral values arranged from largest to smallest, including special combinations such as:
- 1000 → M
- 900 → CM
- 500 → D
- 400 → CD
- 100 → C
- 90 → XC
- 50 → L
- 40 → XL
- 10 → X
- 9 → IX
- 5 → V
- 4 → IV
- 1 → I
The algorithm repeatedly checks whether the current number is greater than or equal to a Roman numeral value. If it is, that symbol is added to the result and the value is subtracted from the number.
For example:
3749 → MMMDCCXLIX
This solution is simple, readable, and efficient. The screenshot also shows the solution being accepted with a 6 ms runtime.
Another great step in strengthening JavaScript problem-solving skills, especially around arrays, loops, greedy algorithms, and string manipulation. 💻🔥
Consistency is the key to improving at coding—one problem at a time!
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Every problem solved is another step forward. Some days will be easy, some problems will make you question everything 😄 — but consistency is what counts.
Keep solving, keep learning, and keep sharing your progress. Looking forward to seeing how far you go! 🚀👏