This problem is an excellent example of how choosing the right algorithm can significantly improve performance and efficiency.

📌 Problem Overview:

Given an array of non-negative integers representing the heights of vertical lines, the goal is to find two lines that, together with the x-axis, can hold the maximum amount of water.

The challenge is to maximize the area between two lines while considering the distance between them and their heights.

💡 My Approach: Two-Pointer Technique

Instead of checking every possible pair of lines using nested loops, I used the two-pointer approach to solve the problem efficiently.

Here's how it works:

✅ Initialize two pointers: one at the beginning and one at the end of the array.

✅ Calculate the width between the pointers.

✅ Find the minimum height of the two lines.

✅ Calculate the area using the formula:

Area = Width × Minimum Height

✅ Update the maximum area whenever a larger value is found.

✅ Move the pointer pointing to the shorter line inward, because moving the taller line cannot improve the area while the shorter line remains the limiting factor.

🔍 Time and Space Complexity:

⏱️ Time Complexity: O(n) — Each pointer moves toward the other at most once per step.

💾 Space Complexity: O(1) — Only a few variables are required.

🏆 What I Learned:

This problem strengthened my understanding of the two-pointer technique, greedy decision-making, and algorithm optimization. It also reminded me that solving coding problems is not just about getting the correct output; it's about finding a solution that is both clean and efficient.

Every problem solved is another step toward becoming a better developer. I'll continue practicing and improving my problem-solving skills! 🚀

Have you solved this problem? Share your approach in the comments!

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